Creates a function that invokes the provided function with its arguments transformed.
Use Array.prototype.map()
to apply transforms
to args
in combination with the spread operator (...
) to pass the transformed arguments to fn
.
代码片段
const overArgs = (fn, transforms) => (...args) => fn(...args.map((val, i) => transforms[i](val)));
使用样例
const square = n => n * n;
const double = n => n * 2;
const fn = overArgs((x, y) => [x, y], [square, double]);
fn(9, 3); // [81, 6]