Returns a list of elements that exist in both arrays.
Create a Set
from b
, then use Array.prototype.filter()
on a
to only keep values contained in b
.
代码片段
const intersection = (a, b) => {
const s = new Set(b);
return [...new Set(a)].filter(x => s.has(x));
};
使用样例
intersection([1, 2, 3], [4, 3, 2]); // [2, 3]