Chunks a list into n
smaller lists.
- Use
math.ceil()
andlen()
to get the size of each chunk. - Use
list()
andrange()
to create a new list of sizen
. - Use
map()
to map each element of the new list to a chunk the length ofsize
. - If the original list can’t be split evenly, the final chunk will contain the remaining elements.
代码实现
from math import ceil
def chunk_into_n(lst, n):
size = ceil(len(lst) / n)
return list(
map(lambda x: lst[x * size:x * size + size],
list(range(n)))
)
使用样例
chunk_into_n([1, 2, 3, 4, 5, 6, 7], 4) # [[1, 2], [3, 4], [5, 6], [7]]