Replaces the last occurrence of a pattern in a string.
- Use
typeof
to determine ifpattern
is a string or a regular expression. - If the
pattern
is a string, use it as thematch
. - Otherwise, use the
RegExp
constructor to create a new regular expression using theRegExp.prototype.source
of thepattern
and adding the'g'
flag to it. UseString.prototype.match()
andArray.prototype.slice()
to get the last match, if any. - Use
String.prototype.lastIndexOf()
to find the last occurrence of the match in the string. - If a match is found, use
String.prototype.slice()
and a template literal to replace the matching substring with the givenreplacement
. - If no match is found, return the original string.
代码实现
const replaceLast = (str, pattern, replacement) => {
const match =
typeof pattern === 'string'
? pattern
: (str.match(new RegExp(pattern.source, 'g')) || []).slice(-1)[0];
if (!match) return str;
const last = str.lastIndexOf(match);
return last !== -1
? `${str.slice(0, last)}${replacement}${str.slice(last + match.length)}`
: str;
};
replaceLast('abcabdef', 'ab', 'gg'); // 'abcggdef'
replaceLast('abcabdef', /ab/, 'gg'); // 'abcggdef'
replaceLast('abcabdef', 'ad', 'gg'); // 'abcabdef'
replaceLast('abcabdef', /ad/, 'gg'); // 'abcabdef'
翻译自:https://www.30secondsofcode.org/js/s/replace-last-occurrence