30秒学会 JavaScript 片段 – Check if arrays have same contents

Checks if two arrays contain the same elements regardless of order.

• Use a for...of loop over a Set created from the values of both arrays.
• Use Array.prototype.filter() to compare the amount of occurrences of each distinct value in both arrays.
• Return false if the counts do not match for any element, true otherwise.

代码实现

const haveSameContents = (a, b) => {
  for (const v of new Set([...a, ...b]))
    if (a.filter(e => e === v).length !== b.filter(e => e === v).length)
      return false;
  return true;
};

haveSameContents([1, 2, 4], [2, 4, 1]); // true

翻译自：https://www.30secondsofcode.org/js/s/arrays-have-same-contents