title: is_contained_in
tags: list,intermediate
Returns True
if the elements of the first list are contained in the second one regardless of order, False
otherwise.
Use count()
to check if any value in a
has more occurences than it has in b
, returning False
if any such value is found, True
otherwise.
代码实现
def is_contained_in(a, b):
for v in set(a):
if a.count(v) > b.count(v):
return False
return True
使用样例
is_contained_in([1, 4], [2, 4, 1]) # True