Checks if a string is an anagram of another string (case-insensitive, ignores spaces, punctuation and special characters).
Use isalnum()
to filter out non-alphanumeric characters, lower()
to transform each character to lowercase.
Use collections.Counter
to count the resulting characters for each string and compare the results.
代码实现
from collections import Counter
def is_anagram(s1, s2):
return Counter(
c.lower() for c in s1 if c.isalnum()
) == Counter(
c.lower() for c in s2 if c.isalnum()
)
使用样例
is_anagram("#anagram", "Nag a ram!") # True