Takes any number of iterable objects or objects with a length property and returns the longest one.
- Use
max()
withlen()
as thekey
to return the item with the greatest length. - If multiple items have the same length, the first one will be returned.
代码实现
def longest_item(*args):
return max(args, key = len)
使用样例
longest_item('this', 'is', 'a', 'testcase') # 'testcase'
longest_item([1, 2, 3], [1, 2], [1, 2, 3, 4, 5]) # [1, 2, 3, 4, 5]
longest_item([1, 2, 3], 'foobar') # 'foobar'