Converts an integer to its roman numeral representation.
Accepts value between 1
and 3999
(both inclusive).
- Create a lookup list containing tuples in the form of (roman value, integer).
- Use a
for
loop to iterate over the values inlookup
. - Use
divmod()
to updatenum
with the remainder, adding the roman numeral representation to the result.
代码实现
def to_roman_numeral(num):
lookup = [
(1000, 'M'),
(900, 'CM'),
(500, 'D'),
(400, 'CD'),
(100, 'C'),
(90, 'XC'),
(50, 'L'),
(40, 'XL'),
(10, 'X'),
(9, 'IX'),
(5, 'V'),
(4, 'IV'),
(1, 'I'),
]
res = ''
for (n, roman) in lookup:
(d, num) = divmod(num, n)
res += roman * d
return res
使用样例
to_roman_numeral(3) # 'III'
to_roman_numeral(11) # 'XI'
to_roman_numeral(1998) # 'MCMXCVIII'
翻译自:https://www.30secondsofcode.org/python/s/to-roman-numeral