Gets the current URL without any parameters or fragment identifiers.
- Use
String.prototype.replace()
with an appropriate regular expression to remove everything after either'?'
or'#'
, if found.
代码实现
const getBaseURL = url => url.replace(/[?#].*$/, '');
getBaseURL('http://url.com/page?name=Adam&surname=Smith');
// 'http://url.com/page'