30秒学会 JavaScript 片段 · 2022年5月22日

30秒学会 JavaScript 片段 – JavaScript Data Structures – Linked List

Definition

A linked list is a linear data structure that represents a collection of elements, where each element points to the next one. The first element in the linked list is the head and the last element is the tail.

JavaScript Linked List visualization

Each element of a linked list data structure must have the following properties:

  • value: The value of the element
  • next: A pointer to the next element in the linked list (null if there is none)

The main properties of a linked list data structure are:

  • size: The number of elements in the linked list
  • head: The first element in the linked list
  • tail: The last element in the linked list

The main operations of a linked list data structure are:

  • insertAt: Inserts an element at the specific index
  • removeAt: Removes the element at the specific index
  • getAt: Retrieves the element at the specific index
  • clear: Empties the linked list
  • reverse: Reverses the order of elements in the linked list

Implementation

代码实现

class LinkedList {
  constructor() {
    this.nodes = [];
  }

  get size() {
    return this.nodes.length;
  }

  get head() {
    return this.size ? this.nodes[0] : null;
  }

  get tail() {
    return this.size ? this.nodes[this.size - 1] : null;
  }

  insertAt(index, value) {
    const previousNode = this.nodes[index - 1] || null;
    const nextNode = this.nodes[index] || null;
    const node = { value, next: nextNode };

    if (previousNode) previousNode.next = node;
    this.nodes.splice(index, 0, node);
  }

  insertFirst(value) {
    this.insertAt(0, value);
  }

  insertLast(value) {
    this.insertAt(this.size, value);
  }

  getAt(index) {
    return this.nodes[index];
  }

  removeAt(index) {
    const previousNode = this.nodes[index - 1];
    const nextNode = this.nodes[index + 1] || null;

    if (previousNode) previousNode.next = nextNode;

    return this.nodes.splice(index, 1);
  }

  clear() {
    this.nodes = [];
  }

  reverse() {
    this.nodes = this.nodes.reduce(
      (acc, { value }) => [{ value, next: acc[0] || null }, ...acc],
      []
    );
  }

  *[Symbol.iterator]() {
    yield* this.nodes;
  }
}
  • Create a class with a constructor that initializes an empty array, nodes, for each instance.
  • Define a size getter, that returns that uses Array.prototype.length to return the number of elements in the nodes array.
  • Define a head getter, that returns the first element of the nodes array or null if empty.
  • Define a tail getter, that returns the last element of the nodes array or null if empty.
  • Define an insertAt() method, which uses Array.prototype.splice() to add a new object in the nodes array, updating the next key of the previous element.
  • Define two convenience methods, insertFirst() and insertLast() that use the insertAt() method to insert a new element at the start or end of the nodes array respectively.
  • Define a getAt() method, which retrieves the element in the given index.
  • Define a removeAt() method, which uses Array.prototype.splice() to remove an object in the nodes array, updating the next key of the previous element.
  • Define a clear() method, which empties the nodes array.
  • Define a reverse() method, which uses Array.prototype.reduce() and the spread operator (...) to reverse the order of the nodes array, updating the next key of each element appropriately.
  • Define a generator method for Symbol.iterator, which delegates to the nodes array’s iterator using the yield* syntax.

使用样例

const list = new LinkedList();

list.insertFirst(1);
list.insertFirst(2);
list.insertFirst(3);
list.insertLast(4);
list.insertAt(3, 5);

list.size;                      // 5
list.head.value;                // 3
list.head.next.value;           // 2
list.tail.value;                // 4
[...list.map(e => e.value)];    // [3, 2, 1, 5, 4]

list.removeAt(1);               // 2
list.getAt(1).value;            // 1
list.head.next.value;           // 1
[...list.map(e => e.value)];    // [3, 1, 5, 4]

list.reverse();
[...list.map(e => e.value)];    // [4, 5, 1, 3]

list.clear();
list.size;                      // 0

翻译自:https://www.30secondsofcode.org/js/s/data-structures-linked-list