Checks if two numbers are approximately equal to each other.
Use Math.abs()
to compare the absolute difference of the two values to epsilon
.
Omit the third parameter, epsilon
, to use a default value of 0.001
.
代码片段
const approximatelyEqual = (v1, v2, epsilon = 0.001) => Math.abs(v1 - v2) < epsilon;
使用样例
approximatelyEqual(Math.PI / 2.0, 1.5708); // true