title: have_same_contents
tags: list,intermediate
Returns True
if two lists contain the same elements regardless of order, False
otherwise.
Use set()
on the combination of both lists to find the unique values.
Iterate over them with a for
loop comparing the count()
of each unique value in each list.
Return False
if the counts do not match for any element, True
otherwise.
代码实现
def have_same_contents(a, b):
for v in set(a + b):
if a.count(v) != b.count(v):
return False
return True
使用样例
have_same_contents([1, 2, 4], [2, 4, 1]) # True