Returns every nth element in a list.
Use [nth-1::nth] to create a new list that contains every nth element of the given list.
代码实现
def every_nth(lst, nth):
return lst[nth - 1::nth]使用样例
every_nth([1, 2, 3, 4, 5, 6], 2) # [ 2, 4, 6 ]Returns every nth element in a list.
Use [nth-1::nth] to create a new list that contains every nth element of the given list.
def every_nth(lst, nth):
return lst[nth - 1::nth]every_nth([1, 2, 3, 4, 5, 6], 2) # [ 2, 4, 6 ]