Returns a list of elements that exist in both lists.
Create a set
from a
and b
, then use the built-in set operator &
to only keep values contained in both sets, then transform the set
back into a list
.
代码实现
def intersection(a, b):
_a, _b = set(a), set(b)
return list(_a & _b)
使用样例
intersection([1, 2, 3], [4, 3, 2]) # [2, 3]