Returns True
if the provided function returns True
for at least one element in the list, False
otherwise.
Use any()
in combination with map()
and fn
to check if fn
returns True
for any element in the list.
代码实现
def some(lst, fn=lambda x: x):
return any(map(fn, lst))
使用样例
some([0, 1, 2, 0], lambda x: x >= 2 ) # True
some([0, 0, 1, 0]) # True